
Circular Motion Question?
A 100g bead is free teo slide along an 80 cm long piece of string ABC. The ends of the string are attached to a vertical pole at A and C, which are 40cm apart. When the pole is rotated about its axis, AB becomes horizontal. a) Find the tension in the string, b) Find the speed of the bead at B.
I asked this question 3 times to my tutor and he keeps beating around the bush and not giving me any assistance at all. HELP!
Based on your description, A and C are two points on a vertical pole, with A being 40 cm above C. The string makes a loop by being connected at two ends to these two points, and the 100 g bead is allowed to move along the string. If this is the case, then B must be some point along the string.
However, if you rotate the pole such that the bead undergoes circular motion, its position (B) can never be horizontal with A. This is because when it is in circular motion, the vertical forces must be in equilibrium; the weight of the bead and the rest of the string acts downwards, and the only upward force comes from the tension in the string in segment AB.
When AB is horizontal, the tension has no component in the vertical direction, and you cannot balance the forces. In other words, the bead will always be lower than the higher point to which the string attaches.
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